document.write( "Question 219653: A man invested $6000, part of it at 5% simple interest and the rest at 7% simple interest. If his annual interest income is $372, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #165149 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .07x+.05(6,000-x)=372 \n" ); document.write( ".07x+300-.05x=372 \n" ); document.write( ".02x=372-300 \n" ); document.write( ".02x=72 \n" ); document.write( "x=72/.02 \n" ); document.write( "x=3,600 amount invested @ 7%. \n" ); document.write( "6,000-3,600=2,400 amount invested @ 5%. \n" ); document.write( "Proof: \n" ); document.write( ".07*3,600+.05*2,400=372 \n" ); document.write( "252+120=372 \n" ); document.write( "372=372 \n" ); document.write( " |