document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=219640>Question 219640</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If five times the lesser of two consecutive integers is added to three times the greater, the result is 59. Find the integers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165148 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165148\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x & x+1 be the 2 integers.<BR>\n" );
document.write( "5x+3(x+1)=59<BR>\n" );
document.write( "5x+3x+3=59<BR>\n" );
document.write( "8x=59-3<BR>\n" );
document.write( "8x=56<BR>\n" );
document.write( "x=56/8<BR>\n" );
document.write( "x=7 ans for the first integer.<BR>\n" );
document.write( "7+1=8 ans. for the second integer.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "5*7+3*8=59<BR>\n" );
document.write( "35+24=59<BR>\n" );
document.write( "59=59<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );