document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=219366>Question 219366</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Warren has 40 coins (all nickels, dimes, and quarters) worth $4.05.  He has 7 more nickels than dimes.  How many quarters does Warren have?  I have been stumped for over an hour with this question.  Can you help? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165127 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165127\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Warren has 40 coins (all nickels, dimes, and quarters) worth $4.05. He has 7 more nickels than dimes. How many quarters does Warren have?<BR>\n" );
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document.write( "Write an equation for each statement:<BR>\n" );
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document.write( "\"Warren has 40 coins\"<BR>\n" );
document.write( "n + d + q = 40<BR>\n" );
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document.write( "\"(all nickels, dimes, and quarters) worth $4.05.\"<BR>\n" );
document.write( ".05n + .10d + .25q = 4.05<BR>\n" );
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document.write( "\"He has 7 more nickels than dimes.\"<BR>\n" );
document.write( "n = d + 7<BR>\n" );
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document.write( " How many quarters does Warren have?<BR>\n" );
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document.write( "Substitute (d+7) for n in both equations, simplify, results:<BR>\n" );
document.write( "(d+7) + d + q = 40<BR>\n" );
document.write( "2d + q = 40 - 7<BR>\n" );
document.write( "2d + q = 33<BR>\n" );
document.write( "q = (33-2d); can use this for substitution<BR>\n" );
document.write( "and<BR>\n" );
document.write( ".05(d+7) + .10d + .25q = 4.05<BR>\n" );
document.write( ".05d + .35 + .10d + .25q = 4.05<BR>\n" );
document.write( ".15d + .25q = 4.05 - .35<BR>\n" );
document.write( ".15d + .25d = 3.70<BR>\n" );
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document.write( "Substitute (33-2d) for q in the above equation<BR>\n" );
document.write( ".15d + .25(33-2d) = 3.70<BR>\n" );
document.write( ".15d + 8.25 - .5d = 3.70<BR>\n" );
document.write( ".15d -.5d = 3.70 - 8.25<BR>\n" );
document.write( "-.35d = -4.55<BR>\n" );
document.write( "d = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-4.55%29%2F%28-.35%29 ALIGN=MIDDLE  ALT=\"%28-4.55%29%2F%28-.35%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "d = +13 dimes<BR>\n" );
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document.write( "Find n using n = d+7<BR>\n" );
document.write( "n = 13 + 7<BR>\n" );
document.write( "n = 20 nickels<BR>\n" );
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document.write( "Find q using q = (33-2d)<BR>\n" );
document.write( "q = 33 - 2(13)<BR>\n" );
document.write( "q = 33 - 26<BR>\n" );
document.write( "q = 7 quarters, which is what they asked for<BR>\n" );
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document.write( "Check solution in the total$ equation<BR>\n" );
document.write( ".05(20) + .10(13) + .25q(7) = <BR>\n" );
document.write( "1.00 + 1.30 + 1.75 = 4.05<BR>\n" );
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