document.write( "Question 219570: A rubber ball is dropped from the height of 13.5 feet. After each bounce the ball only goes up by 60% of what it did on the previous bounce. How high will the ball go after the 38th bounce? I took the 13.5x .6 for the 1st bounce which is 8.1Ft. and the 2nd bounce is 4.9ft. and the third is 2.9ft. I could do this for all the bounces but it would take me forever. How can I write a formula to just put in bounce to get height? \n" ); document.write( "
Algebra.Com's Answer #165092 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
I'll try to write a general formula.
\n" ); document.write( "After the 1st and succeeding bounces,
\n" ); document.write( "\"h+=+.6%2A13.5\"
\n" ); document.write( "\"h+=+.6%2A.6%2A13.5\"
\n" ); document.write( "\"h+=+.6%2A.6%2A.6%2A13.5\"
\n" ); document.write( "It looks like the formula would be
\n" ); document.write( "\"h+=+13.5%2A.6%5En\" where \"n\" is the number of bounces
\n" ); document.write( "and \"h\" is the height after that bounce
\n" ); document.write( "After \"38\" bounces,
\n" ); document.write( "\"h+=+13.5%2A.6%5E38\"
\n" ); document.write( "\"h+=+13.5%2A3.713%2A10%5E%28-9%29\"
\n" ); document.write( "\"h+=+5.0128%2A10%5E%28-8%29\" ft
\n" ); document.write( "How much is that in millionths of an inch?
\n" ); document.write( "\"10%5E6%2A12+=+1.2%2A10%5E5\" millionths of inch/ft
\n" ); document.write( "\"h+=+5.0128%2A10%28-8%29%2A1.2%2A10%5E5\"
\n" ); document.write( "\"h+=+6.015%2A10%5E%28-3%29\"
\n" ); document.write( "That looks like \"h+=+6.015\" billionths
\n" ); document.write( "of an inch after the 38th bounce
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