document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=219561>Question 219561</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I understand a and c of this problem but I cannot figure out b and d because of the month to days thing. The question is;\r<BR>\n" );
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document.write( "Newborn blue whales are approximately 24 feet long and weigh 3 tons. Young whales are nursed for 7 months, and by the time of weaning they often are 53 feet long and weigh 23 tons. Let L and W denote the length (in feet) and the weight (in tons), respectively, of a whale that is t months of age.\r<BR>\n" );
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document.write( "a.) If L and t are linearly related, express L in terms of t.<BR>\n" );
document.write( "L=mt+b<BR>\n" );
document.write( "53=m(7)+24<BR>\n" );
document.write( "29/7=m<BR>\n" );
document.write( "L=(29/7)m+24\r<BR>\n" );
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document.write( "b.) What is the daily increase in the length of a young whale? (Use 1 month= 30 days)<BR>\n" );
document.write( "???<BR>\n" );
document.write( "L=(29/7)?+24\r<BR>\n" );
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document.write( "c.) IF W and t are linearly related, express W in terms of t.<BR>\n" );
document.write( "W=mt+c<BR>\n" );
document.write( "23=m(7)+3<BR>\n" );
document.write( "20/7=m<BR>\n" );
document.write( "W=(20/7)m+3\r<BR>\n" );
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document.write( "d.) What is the daily increase in the weight of a young whale?<BR>\n" );
document.write( "W=(20/7)?+3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #165083 by </B><A HREF=/tutors/aboutme.mpl?userid=jsmallt9><B>jsmallt9(3758)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jsmallt9><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=165083\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a.) If L and t are linearly related, express L in terms of t.<BR>\n" );
document.write( "L=mt+b<BR>\n" );
document.write( "53=m(7)+24<BR>\n" );
document.write( "29/7=m<BR>\n" );
document.write( "So far so good.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=red%28ERROR%29 ALIGN=MIDDLE  ALT=\"red%28ERROR%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > L=(29/7)m+24<BR>\n" );
document.write( "Actually this should be<BR>\n" );
document.write( "L=(29/7)t+24<br><BR>\n" );
document.write( "b.) What is the daily increase in the length of a young whale? (Use 1 month= 30 days)<BR>\n" );
document.write( "In part (a) you figured out the slope of the linear relationship between length and age. The slope represents how much the length changes per unit increase in the age. Since the time, t, is measured in months the slope is how many feet the length increase for each month. So the whale increases in length 29/7 feet per month. To find out what this is per day (and since we're told to use 1 month = 30 days), just divide by 30. The daily increase in length = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2829%2F7%29%2F30+=+%2829%2F7%29%281%2F30%29+=+29%2F210 ALIGN=MIDDLE  ALT=\"%2829%2F7%29%2F30+=+%2829%2F7%29%281%2F30%29+=+29%2F210\"   DISABLED_style= \"max-width:90%; height:auto;\" > feet per day.<br><BR>\n" );
document.write( "c.) IF W and t are linearly related, express W in terms of t.<BR>\n" );
document.write( "W=mt+c<BR>\n" );
document.write( "23=m(7)+3<BR>\n" );
document.write( "20/7=m<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=red%28ERROR%29 ALIGN=MIDDLE  ALT=\"red%28ERROR%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > W=(20/7)m+3<BR>\n" );
document.write( "Again, this should be<BR>\n" );
document.write( "W=(20/7)t+3<br>\r<BR>\n" );
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document.write( "d.) What is the daily increase in the weight of a young whale?<BR>\n" );
document.write( "With the same logic as part (b), the daily increase would be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2820%2F7%29%2F30+=+%2820%2F7%29%281%2F30%29+=+20%2F210+=+2%2F21 ALIGN=MIDDLE  ALT=\"%2820%2F7%29%2F30+=+%2820%2F7%29%281%2F30%29+=+20%2F210+=+2%2F21\"   DISABLED_style= \"max-width:90%; height:auto;\" > tons per day. </SPAN>\n" );
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