document.write( "Question 219497: The perimeter of the triangle is 48centimeters. The longest side is 6 centimeters less than the sum of the other two sides. Twice the shortest side is 5 centimeters less than the longest side. Find the lengths of each side.\r
\n" ); document.write( "\n" ); document.write( "I began by trying to come up with the equations: (a=shortest side; b=middle, c=longest side; and P=48)\r
\n" ); document.write( "\n" ); document.write( "a+b+c=48
\n" ); document.write( "2a=5-c
\n" ); document.write( "c=6-(a+b)
\n" ); document.write( "
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Algebra.Com's Answer #165046 by checkley77(12844)\"\" \"About 
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a+b+c=48
\n" ); document.write( "c=a+b-6
\n" ); document.write( "2a=c-5
\n" ); document.write( "a+b+(a+b-6)=48
\n" ); document.write( "2a+2b-6=48
\n" ); document.write( "2a=2b=48+6
\n" ); document.write( "2a+2b=54
\n" ); document.write( "a+b=27
\n" ); document.write( "27+c=48
\n" ); document.write( "c=48-27
\n" ); document.write( "c=21 ans. for the longest side.
\n" ); document.write( "2a=21-5
\n" ); document.write( "2a=16
\n" ); document.write( "2a=16/2
\n" ); document.write( "a=8 ans.
\n" ); document.write( "8+b=27
\n" ); document.write( "b=27-8
\n" ); document.write( "b=19 ans.
\n" ); document.write( "Proof:
\n" ); document.write( "8+19+21=48
\n" ); document.write( "48=48
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