document.write( "Question 219470: 1.Find an equation of a line that passes through the points (-2,-3) and (-1,1).\r
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document.write( "y=m(x-x1)+y1
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document.write( "y=4(x-(-2) + (-3)
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document.write( "y=4x +8 -3
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document.write( "y=4x + 5 (answer) Is this correct?\r
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document.write( "2. Find the equation of the line that contains the point (0,3) and is perpendicular to the line y=1/2X -1. My answer: y=-2x+1 Is this correct?\r
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document.write( "3. Find x intercept and y-intercept for the line with the equation y=4x + 1/2 and sketch the graph.\r
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document.write( "Y= 1/2
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document.write( "x= -2 Is this correct. \n" );
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Algebra.Com's Answer #165027 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! 1.Find an equation of a line that passes through the points (-2,-3) and (-1,1). \n" ); document.write( "y=m(x-x1)+y1 \n" ); document.write( "y=4(x-(-2) + (-3) \n" ); document.write( "y=4x +8 -3 \n" ); document.write( "y=4x + 5 (answer) Is this correct? \n" ); document.write( "If you sub for x and y, both points satisfy the eqn, so it's correct. \n" ); document.write( "--------------------------- \n" ); document.write( "2. Find the equation of the line that contains the point (0,3) and is perpendicular to the line y=1/2X -1. \n" ); document.write( "My answer: y=-2x+1 Is this correct? \n" ); document.write( "The point (0,3) isn't on the line, so it's not correct. \n" ); document.write( "The slope, m, is -2 \n" ); document.write( "y-3 = -2x \n" ); document.write( "y = -2x + 3 \n" ); document.write( "------------- \n" ); document.write( "3. Find x intercept and y-intercept for the line with the equation y=4x + 1/2 and sketch the graph. \n" ); document.write( "Y= 1/2 \n" ); document.write( "is the y-intercept \n" ); document.write( "-------------- \n" ); document.write( "-------------- \n" ); document.write( "x= -2 Is this correct. \n" ); document.write( "--------------- \n" ); document.write( "x-intercept: \n" ); document.write( "y = 0 \n" ); document.write( "0 = 4x + 1/2 \n" ); document.write( "x = -1/8 \n" ); document.write( " \n" ); document.write( " |