document.write( "Question 219415: Please help me solve the problem
\n" ); document.write( "For the point slope equation given, state the slope and the point on the graph used in creating the equation.
\n" ); document.write( "y= 10/7(x-11)
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Algebra.Com's Answer #165004 by jsmallt9(3759)\"\" \"About 
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The general point-slope form is:
\n" ); document.write( "\"y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29\"
\n" ); document.write( "where m is the slope and (\"x%5B1%5D\", \"y%5B1%5D\") is a point on the line.

\n" ); document.write( "In your equation:
\n" ); document.write( "\"y=+%2810%2F7%29%28x-11%29\"
\n" ); document.write( "we can see that the m is 10/7 and that \"x%5B1%5D\" is 11. But what is the \"y%5B1%5D\"? Your equation has just \"y\" on the left side. It's \"supposed\" to be \"y+-+y%5B1%5D\". What would \"y%5B1%5D\" have to be in order for \"y+-+y%5B1%5D\" to be just \"y\"? In other words, y minus what number is equal to y? I hope by now that it is obvious that \"y%5B1%5D+=+0\".

\n" ); document.write( "So the slope is 10/7 and the point on the graph is (11, 0).
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