document.write( "Question 219413: out of a tank which is 3/4th full 21 litres of water is drawn out. the tank is now 2/5th full.what is the capacity of tank in litres? \n" ); document.write( "

Algebra.Com's Answer #165000 by Theo(13342) $\"\"$ $\"About$

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let T = capacity of the tank when it is full.
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\n" ); document.write( "(3/4) * T - 21 = (2/5) * T
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\n" ); document.write( "This equation states that three fourths of the tank capacity minus 21 liters equals two fifths of the tank capacity.
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\n" ); document.write( "Solve for T:
\n" ); document.write( "(3/4) * T - 21 = (2/5) * T
\n" ); document.write( "Subtract (2/5) * T and add 21 to both sides of this equation to get:
\n" ); document.write( "(3/4) * T - (1/5) * T = 21
\n" ); document.write( "Multiply both sides of this equation by 20 to get:
\n" ); document.write( "15 * T - 8 * T = 21 * 20
\n" ); document.write( "Simplify to get:
\n" ); document.write( "7 * T = 21 * 20
\n" ); document.write( "Divide both sides of this equation by 7 to get:
\n" ); document.write( "T = 21 * 20 / 7
\n" ); document.write( "Simplify to get:
\n" ); document.write( "T = 60
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\n" ); document.write( "The capacity of the tank when it is full is 60 liters.
\n" ); document.write( "3/4 * this is 45 liters.
\n" ); document.write( "Substract 21 from that to get:
\n" ); document.write( "24 liters.
\n" ); document.write( "24 liters / 60 = 2/5
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\n" ); document.write( "Capacity of the tank is 60 liters. Remove 21 liters from it when it is only 3/4 full and you are left with 24 liters which is 2/5 of the capacity of the tank.
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\n" ); document.write( "That's your answer.
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