document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=219367>Question 219367</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if one-half of the supplement of an angel is six degrees less than twice the complement the measure of the angel is ______ degrees.\r<BR>\n" );
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document.write( "I did not really know how to write this equation. Please help me.<BR>\n" );
document.write( "1/2 (180-x)=6-2(90-x)   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #164972 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=164972\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .5(180-x)=2(90-x)-6<BR>\n" );
document.write( "90-.5x=180-2x-6<BR>\n" );
document.write( "1.5x=90-6<BR>\n" );
document.write( "1.5x=84<BR>\n" );
document.write( "x=56<BR>\n" );
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document.write( "180-56=124/2=62<BR>\n" );
document.write( "90-56=34*2=68-6=62<BR>\n" );
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document.write( "Your basic setup was good except that you need to subtract the 6 from 2(90-x)<BR>\n" );
document.write( "reverse what you had.<BR>\n" );
document.write( "Good luck<BR>\n" );
document.write( "Bob </SPAN>\n" );
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