document.write( "Question 219289: A homing device left its home to deliver a mesage. on takeoff, the device encountered a tailwind of 15 mph and made the delivery in 5 minutes. The return trip into the wind took 10 minutes. How fast does the device fly in still air?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "llaws@mrhs.com
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #164940 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A homing device left its home to deliver a mesage. on takeoff, the device encountered a tailwind of 15 mph and made the delivery in 5 minutes. The return trip into the wind took 10 minutes. How fast does the device fly in still air?
\n" ); document.write( "----------
\n" ); document.write( "Let x be the rate of the device in still air.
\n" ); document.write( "------------------
\n" ); document.write( "Downwind DATA:
\n" ); document.write( "time = 1/12 hr ; rate = x+15 mph ; distance = rt = (1/12)(x+15) miles
\n" ); document.write( "-------------------------
\n" ); document.write( "Upwind DATA:
\n" ); document.write( "time = 1/6 hr ; rate = x-15 mph ; distance = rt = (1/6)(x-15) miles
\n" ); document.write( "-------------------------
\n" ); document.write( "Equation:
\n" ); document.write( "distance = distance
\n" ); document.write( "(1/12)(x+15) = (1/6)(x-15)
\n" ); document.write( "Multiply both sides by 12 to get:
\n" ); document.write( "x+15 = 2x-30
\n" ); document.write( "x = 45 mph (speed of the device in still air)
\n" ); document.write( "==================================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );