document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=219270>Question 219270</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Fred leaves his house for work, which is exactly 2 miles away. After Fred has traveled 2/3 mile he must turn around to pick up some papers. After he travels 1/6 mile back home, how far away from work is he?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #164929 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=164929\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Fred leaves his house for work, which is exactly 2 miles away. After Fred has traveled 2/3 mile he must turn around to pick up some papers. After he travels 1/6 mile back home, how far away from work is he? <BR>\n" );
document.write( ":<BR>\n" );
document.write( "2 - (2/3 - 1/6)<BR>\n" );
document.write( "Use 6ths<BR>\n" );
document.write( "12/6 - (4/6 - 1/6) = <BR>\n" );
document.write( "12/6 - 3/6 =  9/6 = 1.5 mi from work </SPAN>\n" );
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