document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=3754>Question 3754</A>: <I><SPAN STYLE=\"word-break: break-all;\">               2      t<BR>\n" );
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document.write( "              t     5t-12 \r<BR>\n" );
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document.write( "on this one you take 2 divided by t = t divided by 5t-12<BR>\n" );
document.write( "I just need to know what to do with this problem. Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1649 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1649\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiply both sides by 5t-12, so that the 5t-12 cancels with the 5t-12 on the denominator on the right hand side. And then multiply both sides by t, so that the t on the left hand side will cancel with the denominator. This is basically what people call cross-multiplying:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282%2Ft%29+=+%28%28t%29%2F%285t-12%29%29 ALIGN=MIDDLE  ALT=\"%282%2Ft%29+=+%28%28t%29%2F%285t-12%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282%285t-12%29%2Ft%29+=+%28%28t%285t-12%29%29%2F%285t-12%29%29 ALIGN=MIDDLE  ALT=\"%282%285t-12%29%2Ft%29+=+%28%28t%285t-12%29%29%2F%285t-12%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282%285t-12%29%2Ft%29+=+t ALIGN=MIDDLE  ALT=\"%282%285t-12%29%2Ft%29+=+t\"   DISABLED_style= \"max-width:90%; height:auto;\" > and then:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282t%285t-12%29%2Ft%29+=+t%5E2 ALIGN=MIDDLE  ALT=\"%282t%285t-12%29%2Ft%29+=+t%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%285t-12%29+=+t%5E2 ALIGN=MIDDLE  ALT=\"2%285t-12%29+=+t%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >. You should be able to get from your question to this line in one line - i have just shown the whole process.\r<BR>\n" );
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document.write( "Now expand and re-order to get a quadratic:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10t-24+=+t%5E2 ALIGN=MIDDLE  ALT=\"10t-24+=+t%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=t%5E2-10t%2B24+=+0 ALIGN=MIDDLE  ALT=\"t%5E2-10t%2B24+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now look to factorise this. If you cannot see the factors in there, then you will have to use the quadratic formula. I can see the factors though:\r<BR>\n" );
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document.write( "(x-6)(x-4) = 0\r<BR>\n" );
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document.write( "so now, either x-6=0 or x-4=0\r<BR>\n" );
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document.write( "so, x=6 or x=4\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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