document.write( "Question 219152: if five is subtracted from twice a number and this difference is tripled, the result is one more than four times the number. find the number. Domain:{8, 9, 10}\r
\n" ); document.write( "\n" ); document.write( "I tried to set the problem up as: 2x-5+3(2x-5)=1+4x where the first number is 2x-5 and the 2ns number is 3(2x-5) what did I do wrong?
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Algebra.Com's Answer #164862 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
The equation should be \"3%282x-5%29=1%2B4x\". We're not looking for two numbers. We just want to find that one unknown value of 'x'.\r
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\n" ); document.write( "\n" ); document.write( "\"3%282x-5%29=1%2B4x\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"6x-15=1%2B4x\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"6x=1%2B4x%2B15\" Add \"15\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"6x-4x=1%2B15\" Subtract \"4x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"2x=1%2B15\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"2x=16\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2816%29%2F%282%29\" Divide both sides by \"2\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=8\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=8\" which means that the unknown number is 8.
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