document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=219053>Question 219053</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3 qt. of a sugar solution was mixed with 4 qt. of a 4% sugar solution to make a 40% sugar solution. Find the percent concentration of the first solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #164857 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=164857\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> OK<BR>\n" );
document.write( "Let x=the percent sugar in the 3qt solution<BR>\n" );
document.write( "Now we know that the amount of pure sugar in the 3qt solution (3x) plus the amount of pure sugar in the 4qt solution (0.04*4) has to equal the amount of pure sugar in the final solution (7*0.40), so our equation to solve is:\r<BR>\n" );
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document.write( "3x+0.04*4=0.40*7 simplify<BR>\n" );
document.write( "3x+0.16=2.8  subtract 0.16 from each side<BR>\n" );
document.write( "3x+0.16-0.16=2.8-0.16  collect like terms<BR>\n" );
document.write( "3x=2.64  divide each side by 3<BR>\n" );
document.write( "x=0.88 or 88%----the percent sugar in the 3qt solution\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "3*0.88+4*0.04=0.40*7<BR>\n" );
document.write( "2.64+0.16=2.80<BR>\n" );
document.write( "2.80=2.80\r<BR>\n" );
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document.write( "Hope this helps----ptaylor </SPAN>\n" );
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