document.write( "Question 29786: Geoff has $5000 to invest. He wants to earn $568 in interest in one year. He will invest part of the money at 12% and the other part at 10%. How will he invest to earn $568? \n" ); document.write( "
Algebra.Com's Answer #16484 by ikdeep(226)\"\" \"About 
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Total money to invest = $5000\r
\n" ); document.write( "\n" ); document.write( "Let one part of meoney = $x..........(1)\r
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\n" ); document.write( "\n" ); document.write( "Let other part of meoney = ($5000 - x)...............(2)\r
\n" ); document.write( "\n" ); document.write( "According to question,,,one part is invested at 12% and other part is invested at 10%..and the total money to earn = $568\r
\n" ); document.write( "\n" ); document.write( "So the equation goes like this .....\r
\n" ); document.write( "\n" ); document.write( "12% of one part + 10% of other part = $568\r
\n" ); document.write( "\n" ); document.write( "Putting the values from (1) and (2).we get..\r
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\n" ); document.write( "\n" ); document.write( "12% of $x + 10% of ($5000 - x) = $568\r
\n" ); document.write( "\n" ); document.write( "find the value of x and put them in (1) and (2)...to get answer\r
\n" ); document.write( "\n" ); document.write( "Hope this will help...\r
\n" ); document.write( "\n" ); document.write( "If you are not able to solve further also, contact me again..\r
\n" ); document.write( "\n" ); document.write( "Please feel free to revert back for any further queries\r
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