document.write( "Question 219059: The mean amount of life insurance per household is 110,000 normal distribution a) with a standarf deviation of $40,000 what is the likelihood of selecting a sample with a mean of at least $112,000?
\n" ); document.write( "b) What is the expected shape of the distribution of the sample mean?
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Algebra.Com's Answer #164811 by stanbon(75887)\"\" \"About 
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The mean amount of life insurance per household is 110,000 normal distribution a) with a standard deviation of $40,000 what is the likelihood of selecting a sample with a mean of at least $112,000?
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\n" ); document.write( "z(112,000) = (112,000-110,000)/[40,000] = 2/40
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\n" ); document.write( "P(z>(2/40) = normalcdf((2/40),10) = 0.48
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\n" ); document.write( "b) What is the expected shape of the distribution of the sample mean?
\n" ); document.write( "The sample means will have a normal distribution
\n" ); document.write( "as guaranteed by the Central Limit Theorem.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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