document.write( "Question 219058: 7a+12<6a+3\r
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Algebra.Com's Answer #164810 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"7a%2B12%3C=6a%2B3\" Start with the given inequality.\r
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\n" ); document.write( "\n" ); document.write( "\"7a%3C=6a%2B3-12\" Subtract \"12\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"7a-6a%3C=3-12\" Subtract \"6a\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"a%3C=3-12\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"a%3C=-9\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"a%3C=-9\"
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