document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=218995>Question 218995</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "find two supplementary angles such that the measure of the first angle is 60 degrees less than twice the second? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #164799 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=164799\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=180 or x=180-y<BR>\n" );
document.write( "x=2y-60<BR>\n" );
document.write( "2y-60=180-y<BR>\n" );
document.write( "2y+y=180+60<BR>\n" );
document.write( "3y=240<BR>\n" );
document.write( "y=240/3<BR>\n" );
document.write( "y=80 ans.<BR>\n" );
document.write( "x=180-80<BR>\n" );
document.write( "x=100 ans.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "100=2*80-60<BR>\n" );
document.write( "100=160-60<BR>\n" );
document.write( "100=100 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );