document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=218984>Question 218984</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are complements and one lacks 8 degrees of being twice the other.  What are the angles?  \r<BR>\n" );
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document.write( "I tried:  90 = 2x - 8 + y\r<BR>\n" );
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document.write( "90 + 8 = 2x - 8 + 8 + y<BR>\n" );
document.write( "98 = 2x + y<BR>\n" );
document.write( "49 = x + y\r<BR>\n" );
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document.write( "Stuck here </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #164792 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=164792\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=90 or x=90-y<BR>\n" );
document.write( "x-8=2y<BR>\n" );
document.write( "x=2y+8<BR>\n" );
document.write( "2y+8=90-y<BR>\n" );
document.write( "2y+y=90-8<BR>\n" );
document.write( "3y=82<BR>\n" );
document.write( "y=82/3<BR>\n" );
document.write( "y=27 1/3 ans.<BR>\n" );
document.write( "x=90-27 1/3=62 2/3 ans.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "62 2/3-8=2*27 1/3<BR>\n" );
document.write( "54 2/3=54 2/3 </SPAN>\n" );
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