document.write( "Question 219013: x2+16x+a = (x+b)2 \r
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Algebra.Com's Answer #164790 by jim_thompson5910(35256)\"\" \"About 
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\"x%5E2%2B16x%2Ba=%28x%2Bb%29%5E2\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B16x%2Ba=x%5E2%2B2xb%2Bb%5E2\" FOIL the right side.\r
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\n" ); document.write( "\n" ); document.write( "Take note that the terms 16x and 2xb both have \"x\" terms (without an exponent). So this means that \"16x=2xb\". Divide both sides by 2x to get \"8=b\" or \"b=8\"\r
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\n" ); document.write( "\n" ); document.write( "Notice how the term \"a\" does not have an \"x\" and \"b%5E2\" doesn't have an \"x\" either. So this means that \"a=b%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "Plug in \"b=8\" to get \"a=8%5E2=64\". So \"a=64\"\r
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\n" ); document.write( "\n" ); document.write( "So this tells us that \"x%5E2%2B16x%2B64=%28x%2B8%29%5E2\"
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