document.write( "Question 218932: write the standard form of the equation of the circle that is tangent to x= -2 and has its center at (2, -4) \n" ); document.write( "

Algebra.Com's Answer #164755 by RAY100(1637) $\"\"$ $\"About$

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the standard form for a circle is,,,(x-h)^2 +(y-k)^2 = r^2
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\n" ); document.write( "with (h,k) as center of circle,,and r as radius
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\n" ); document.write( "with center at (2, -4),,,,,h= 2,,,k= -4,,,and radius is the x distance from center to x=-2,,,|(-2-2)| = |(-4)| = 4
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\n" ); document.write( "substituting, (x-2)^2 + (y-(-4) )^2 =4^2 =16
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\n" ); document.write( "(x-2)^2 +(y+4)^2 = 16,,,,answer
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\n" ); document.write( "a rough sketch shows how this is possible on the x-y coordinate system.
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