document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=218922>Question 218922</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the distance between points at (6, -3) and (-1, 4) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #164752 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=164752\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the  distance  formula  is ,,,,d= sqrt{y2-y1)^2 + (x2-x1)^2 }<BR>\n" );
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document.write( "for (6,-30,,,,(-1,4)<BR>\n" );
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document.write( "d= sqrt( -30 -4)^2 + (6-(-1) )^2 }<BR>\n" );
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document.write( "d= sqrt { (-34)^2 + (7)^2 }<BR>\n" );
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document.write( "d=sqrt { 1156 +49 }<BR>\n" );
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document.write( "d=sqrt { 1205)<BR>\n" );
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document.write( "d=34.713<BR>\n" );
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document.write( "a  rough  sketch  always  helps  clarify.<BR>\n" );
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document.write( "the  change  in  y = 34,,,and  the  change  in x= 7,,,c^2 = a^2+b^2,, d^2=34^2+7^2,,,d=34.713,,,ok<BR>\n" );
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