document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=218847>Question 218847</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A distillate flows into an empty 6 gallon drum at spout A and out at spout B.If the rate of flow through A is 2 gallon per hour.How many gallon per hour must flow out at spout B so that the drum is full in exactly 96 hours.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #164731 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=164731\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Rate of flow into the tank at spout A=2 gal/hr<BR>\n" );
document.write( "Let x=rate of flow out at Spout B (gal/hr)\r<BR>\n" );
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document.write( "Net rate of flow into the tank=2-x\r<BR>\n" );
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document.write( "Now we know that net rate of flow into the tank times 96 hrs=6 gal<BR>\n" );
document.write( "So, our equation to solve is:\r<BR>\n" );
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document.write( "(2-x)*96=6<BR>\n" );
document.write( "192-96x=6 subtract 192 from each side<BR>\n" );
document.write( "-96x=6-192<BR>\n" );
document.write( "-96x=-186 divide each side by -96<BR>\n" );
document.write( "x=1.9375 gal/hr----rate of flow out at Spout B (gal/hr)\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "(2-1.9375)*96=6<BR>\n" );
document.write( "0.0625*96=6<BR>\n" );
document.write( "6=6\r<BR>\n" );
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document.write( "Hope this helps----ptaylor </SPAN>\n" );
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