document.write( "Question 29760: find the value of x
\n" ); document.write( "log2x+log2(x-3)=2
\n" ); document.write( "thanks for the help
\n" ); document.write( "Lee Ann \n" ); document.write( "

Algebra.Com's Answer #16470 by Cintchr(481) $\"\"$ $\"About$

You can put this solution on YOUR website!
logb n = p or b^p = n
\n" ); document.write( "b is the base
\n" ); document.write( "p is the power
\n" ); document.write( "n is the answer
\n" ); document.write( "when adding logs of the same base ... you are really multiplying.\r
\n" ); document.write( "\n" ); document.write( "log2x + log2(x-3)=2
\n" ); document.write( "log2 x(x-3) =2
\n" ); document.write( "transform this into the b^p = n form
\n" ); document.write( " $\"2%5E2+=+x%28x-3%29\"$ square 2 and distribute the x to (x-3)
\n" ); document.write( " $\"4+=+x%5E2+-+3x\"$ subtract 4 from both sides
\n" ); document.write( " $\"0+=+x%5E2+-+3x+-+4\"$ factor
\n" ); document.write( " $\"0+=+%28x-4%29%28x%2B1%29\"$ set each quantity equal to zero
\n" ); document.write( "0=x-4 or 0=x+1
\n" ); document.write( "x=4 -1=x \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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