document.write( "Question 218772: if a right triangle has a area 180cm^(2) and hypotenuse 41 cm, find the length of the two legs \n" ); document.write( "
Algebra.Com's Answer #164693 by drj(1380)\"\" \"About 
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If a right triangle has a area 180cm^(2) and hypotenuse 41 cm, find the length of the two legs.\r
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\n" ); document.write( "\n" ); document.write( "Step 1. The Area \"A=ab%2F2=180\" where a and b are legs of the triangle.\r
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\n" ); document.write( "\n" ); document.write( "\"b=360%2Fa\"\r
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\n" ); document.write( "\n" ); document.write( "Step 2. The Pythagorean Theorem is the sum of the squares of the legs (a and b) is equal to the square of the hypotenuse c\r
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\n" ); document.write( "\n" ); document.write( "\"c%5E2=a%5E2%2Bb%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"c%5E2=a%5E2%2B%28360%2Fa%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Step 3. Multiply by a^2 to both sides of the equation to get rid of denominator and c=41.\r
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\n" ); document.write( "\n" ); document.write( "\"41%5E2%2Aa%5E2=a%5E2%2Aa%5E2%2B360%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E4-1681a%5E2%2B360%5E2=0\" \r
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\n" ); document.write( "\n" ); document.write( "Step 4. Let x=a^2 to simplify equation as a quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-1681x%2B129600=0\"\r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-1681x%2B129600+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-1681%29%5E2-4%2A1%2A129600=2307361\".
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\n" ); document.write( " Discriminant d=2307361 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--1681%2B-sqrt%28+2307361+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-1681%29%2Bsqrt%28+2307361+%29%29%2F2%5C1+=+1600\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-1681%29-sqrt%28+2307361+%29%29%2F2%5C1+=+81\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B-1681x%2B129600\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-1681x%2B129600+=+1%28x-1600%29%2A%28x-81%29\"
\n" ); document.write( " Again, the answer is: 1600, 81.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-1681%2Ax%2B129600+%29\"

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\n" ); document.write( "\n" ); document.write( "We have \"x=1600\" and \"x=81\", then \"a%5E2=1600\" and \"a%5E2=81\"\r
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\n" ); document.write( "\n" ); document.write( "Step 5. Taking the square root yields a=40 and a=9.\r
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\n" ); document.write( "\n" ); document.write( "Then b is \"360%2F40=9\" or \"360%2F9=40\".\r
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\n" ); document.write( "\n" ); document.write( "Step 6. ANSWER: The legs of the right triangle are 9 cm and 40 cm.\r
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\n" ); document.write( "\n" ); document.write( "I hope the above steps and explanation were helpful. \r
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\n" ); document.write( "\n" ); document.write( "For Step-By-Step videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry please visit http://www.FreedomUniversity.TV/courses/Trigonometry. \r
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\n" ); document.write( "\n" ); document.write( "Also, good luck in your studies and contact me at john@e-liteworks.com for your future math needs.\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J\r
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\n" ); document.write( "\n" ); document.write( "http://www.FreedomUniversity.TV
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