document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=218689>Question 218689</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Line 1 is described by the equation 3y - 2x = -3.  Line 2 goes through the origin and intersects line 1 at x=6.  What equation describes line 2? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #164691 by </B><A HREF=/tutors/aboutme.mpl?userid=drj><B>drj(1380)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drj><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=drj><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=164691\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Line 1 is described by the equation 3y - 2x = -3. Line 2 goes through the origin and intersects line 1 at x=6. What equation describes line 2?\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Step 1. At x=6 then to find y substitute into 3y-2x=-3\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3y-2%2A6=-3 ALIGN=MIDDLE  ALT=\"3y-2%2A6=-3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Add 12 to both sides of the equation\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3y-12%2B12=-3%2B12 ALIGN=MIDDLE  ALT=\"3y-12%2B12=-3%2B12\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3y=9 ALIGN=MIDDLE  ALT=\"3y=9\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Divide 3 to both sides of the equation\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3y%2F3=9%2F3 ALIGN=MIDDLE  ALT=\"3y%2F3=9%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=3 ALIGN=MIDDLE  ALT=\"y=3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Step 2.  The intersection point is (6,3)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Step 3.  We can find the equation of line 2 with these two points:  (0,0) and (6,3).\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Step 4.  Slope <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=%283-0%29%2F%286-0%29=1%2F2 ALIGN=MIDDLE  ALT=\"m=%283-0%29%2F%286-0%29=1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > and y-intercept b=0 since it passes through the origin (0,0)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Step 5.  ANSWER: The equation is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=x%2F2 ALIGN=MIDDLE  ALT=\"y=x%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "I hope the above steps and explanation were helpful. \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "For Step-By-Step videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry please visit http://www.FreedomUniversity.TV/courses/Trigonometry. \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Also, good luck in your studies and contact me at john@e-liteworks.com for your future math needs.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Respectfully, <BR>\n" );
document.write( "Dr J\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "http://www.FreedomUniversity.TV </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );