document.write( "Question 218663: Two automobiles travel in opposite directions from the same starting point. If the speed of one is twice the speed of the other and they are 190.0 km apart at the end of 2.0 h, what is the speed of the slower car (in m/s)? \n" ); document.write( "

Algebra.Com's Answer #164651 by josmiceli(19441) $\"\"$ $\"About$

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If vehicles are going in opposite directions, they can be treated
\n" ); document.write( "as 1 vehicle going at the combined speed of both
\n" ); document.write( " $\"d+=+r%2At\"$
\n" ); document.write( " $\"190+=+%28r+%2B+2r%29%2A2\"$
\n" ); document.write( "Note that I made things easy by calling rate $\"r+%2B+2r\"$
\n" ); document.write( " $\"190+=+6r\"$
\n" ); document.write( " $\"r+=+31.667\"$
\n" ); document.write( "This is the speed of the slower vehicle
\n" ); document.write( "in km/hr
\n" ); document.write( " $\"31.667\"$ km/hr x $\"1%2F3600\"$ hr/sec x $\"1000\"$ m/km
\n" ); document.write( " $\"31.667+%2A+%281%2F3600%29+%2A+1000+=+8.796\"$ m/s
\n" ); document.write( "The slower car is going 8.796 m/sec
\n" ); document.write( "check answer:
\n" ); document.write( " $\"2r+=+17.593\"$ m/s
\n" ); document.write( " $\"190+%2A+1000+=+%2817.593+%2B+8.796%29%2A2%2A3600\"$
\n" ); document.write( " $\"190000+=+26.389+%2A+7200\"$
\n" ); document.write( " $\"190000+=+189997.867\"$
\n" ); document.write( "Close enough
\n" ); document.write( " \n" ); document.write( "

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