document.write( "Question 29780: 5x - 3 > 12x + 1 \n" ); document.write( "
Algebra.Com's Answer #16461 by hoffy1808(2) ![]() You can put this solution on YOUR website! First step. get both X's on one side \n" ); document.write( " 5x - 3 > 12x + 1 \n" ); document.write( " -5x -5x \n" ); document.write( "----------------------- \n" ); document.write( " -3 > 7x + 1\r \n" ); document.write( "\n" ); document.write( "Now you want to get the 7x alone. \n" ); document.write( " -3 > 7x + 1 \n" ); document.write( " -1 - 1 \n" ); document.write( "--------------- \n" ); document.write( " -4 > 7x\r \n" ); document.write( "\n" ); document.write( "Then you want to get X by its self so divide by 7 \n" ); document.write( " -4 > 7x \n" ); document.write( " / 7 > /7\r \n" ); document.write( "\n" ); document.write( "Your answer = -4/7 is greater than (>) x\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |