document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29764>Question 29764</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the inequality -12<=-3x+6<=12<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16457 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16457\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -12<=-3x+6<=12\r<BR>\n" );
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document.write( "-12<=-3x+6 <BR>\n" );
document.write( "3x=<6+12 (grouping like terms,changing sign while changing side)<BR>\n" );
document.write( "3x=<18<BR>\n" );
document.write( "x=<6 ----(1) <BR>\n" );
document.write( "(dividing by the positive integer 3 and division by a positive quantity does not alter the inequality)\r<BR>\n" );
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document.write( "-3x+6<=12<BR>\n" );
document.write( "-3x=<12-6 (grouping like terms,changing sign while changing side)<BR>\n" );
document.write( "-3x=<6<BR>\n" );
document.write( "x>=6/(-3) (dividing by the negative  integer 3 and division by a negative quantity  alters the inequality and so less than becomes greater  than and of course equality remains the same)<BR>\n" );
document.write( "x>=-2  <BR>\n" );
document.write( "That is -2< = x----(2)  \r<BR>\n" );
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document.write( "From (2) and (1) by transitivity<BR>\n" );
document.write( "we have  -2 =<  x =<6 </SPAN>\n" );
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