document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=218395>Question 218395</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boat travels 60 km upstream, (against the current) in 5 hours. The boat travels the same distance downstream in 3 hours. What is the rate of the boat in still water? \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #164523 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=164523\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT OR D/T=R<BR>\n" );
document.write( "60/5=12 KPH.<BR>\n" );
document.write( "60/3=20 KPH.<BR>\n" );
document.write( "(20-12)/2=8/2=4 KPH IS THE SPEED OF THE CURRENT.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "20-4=16 KPH FOR THE BOAT IN STILL WATER.<BR>\n" );
document.write( "12+4=16 DITTO.\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );