document.write( "Question 218411: I'm at the review section of my Trig book and to be honest, I don't remember what to do here. I think one has to square the root away and square the other side, and subtract the 44, but then I'm not sure. I'd rather not have x^2-44 over 7 equals x, but could that be right?
\n" ); document.write( "\"+sqrt%28+7x+%2B+44+%29+\" = x
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Algebra.Com's Answer #164517 by Alan3354(69443)\"\" \"About 
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\"+sqrt%28+7x+%2B+44+%29+\" = x
\n" ); document.write( "Square both sides
\n" ); document.write( "7x + 44 = x^2
\n" ); document.write( "x^2 - 7x - 44 = 0
\n" ); document.write( "(x-11)*(x+4) = 0
\n" ); document.write( "x = 11
\n" ); document.write( "x = -4
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