document.write( "Question 29765: Hello, I need help tonight...tried this problem at least 6 times. help
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document.write( "The difference of two numbers is 12. Two fifths of the greater number is 6 more than one third of the lesser number. Find both numbers.
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document.write( "I know x-y=12 and 2/5x,1/3y-6, and don't know where to go from there. Please Help. \n" );
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Algebra.Com's Answer #16451 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! Let the first number be x \n" ); document.write( "Let the second number be y \n" ); document.write( "x-y=12 \n" ); document.write( "y=-12+x (subsitution)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Greater number 2x/5 \n" ); document.write( "Lesser number = 1y/3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Equation: \n" ); document.write( " \n" ); document.write( "Multiply the whole equation by 15 to remove the fraction. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Subsitute \n" ); document.write( "6x=90+5(-12+x) \n" ); document.write( "6x=90-60+5x \n" ); document.write( "x=30\r \n" ); document.write( "\n" ); document.write( "y=-12+30 \n" ); document.write( "y=18\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( " \n" ); document.write( "12=12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, the two numbers are 30 and 18 \n" ); document.write( "Paul. \n" ); document.write( " |