document.write( "Question 218352: A third of an angle is 4 more than its supplement. Find both angles. \n" ); document.write( "
Algebra.Com's Answer #164456 by drj(1380)\"\" \"About 
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A third of an angle is 4 more than its supplement. Find both angles.\r
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\n" ); document.write( "\n" ); document.write( "Step 1. Supplementary angles is when two angles add up to 180 degrees.\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Let x be the angle and x/3 be one-third of the angle\r
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\n" ); document.write( "\n" ); document.write( "Step 3. Let 180-x be its supplementary angle.\r
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\n" ); document.write( "\n" ); document.write( "Step 4. x/3=180-x+4=184-x since a third of an angle is 4 more than its supplement.\r
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\n" ); document.write( "\n" ); document.write( "Step 5. Solving yields the following steps:\r
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\n" ); document.write( "\n" ); document.write( "Multiply by three to both sides of the equation to yield\r
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\n" ); document.write( "\n" ); document.write( "\"3%2Ax%2F3=3%2A184-3%2Ax\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=552-3x\"\r
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\n" ); document.write( "\n" ); document.write( "Add 3x to both sides of the equation\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B3x=552\"\r
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\n" ); document.write( "\n" ); document.write( "\"4x=552\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=138\" and \"x=42\"\r
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\n" ); document.write( "\n" ); document.write( "Check: x/3=180-x+4 or 138/3=42+4 this is a true statement.\r
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\n" ); document.write( "\n" ); document.write( "Step 6. ANSWER: The angles are 138 and 42.\r
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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful.\r
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\n" ); document.write( "\n" ); document.write( "For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "And good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J\r
\n" ); document.write( "\n" ); document.write( "http://www.FreedomUniversity.TV\r
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