document.write( "Question 218352: A third of an angle is 4 more than its supplement. Find both angles. \n" ); document.write( "
Algebra.Com's Answer #164456 by drj(1380) You can put this solution on YOUR website! A third of an angle is 4 more than its supplement. Find both angles.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Step 1. Supplementary angles is when two angles add up to 180 degrees.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Step 2. Let x be the angle and x/3 be one-third of the angle\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Step 3. Let 180-x be its supplementary angle.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Step 4. x/3=180-x+4=184-x since a third of an angle is 4 more than its supplement.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Step 5. Solving yields the following steps:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply by three to both sides of the equation to yield\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add 3x to both sides of the equation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: x/3=180-x+4 or 138/3=42+4 this is a true statement.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Step 6. ANSWER: The angles are 138 and 42.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And good luck in your studies!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Respectfully, \n" ); document.write( "Dr J\r \n" ); document.write( "\n" ); document.write( "http://www.FreedomUniversity.TV\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |