document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=218343>Question 218343</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the coordinates of the vertex and the equation of the axis of symmerty for the parabola with the equation 2x^2 + 2x - y = -3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #164439 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=164439\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the coordinates of the vertex and the equation of the axis of symmerty for the parabola with the equation 2x^2 + 2x - y = -3<BR>\n" );
document.write( "y = 2x^2 + 2x + 3<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "The axis of symmetry is x = -b/2a = -2/4<BR>\n" );
document.write( "x = -1/2 is the axis of symmetry.<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "At x = -1/2: y = 1/2 - 1 + 3<BR>\n" );
document.write( "y = 5/2<BR>\n" );
document.write( "Vertex at (-1/2,5/2)<BR>\n" );
document.write( " </SPAN>\n" );
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