document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=218343>Question 218343</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the coordinates of the vertex and the equation of the axis of symmerty for the parabola with the equation 2x^2 + 2x - y = -3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #164438 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=164438\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the coordinates of the vertex and the equation of the axis of symmerty for the parabola with the equation 2x^2 + 2x - y = -3<BR>\n" );
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document.write( "Rearrange:<BR>\n" );
document.write( "2x^2 + 2x + ? = y-3<BR>\n" );
document.write( "---<BR>\n" );
document.write( "2(x^2 + x + (1/2)^2) = y-3+2(1/2)^2<BR>\n" );
document.write( "---<BR>\n" );
document.write( "2(x+(1/2))^2 = y-(11/4)<BR>\n" );
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document.write( "Vertex=(-1/2 , 11/4)<BR>\n" );
document.write( "Axis of symmetry: x = -1/2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );