document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=218339>Question 218339</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I trying to rationalize the denominator but I am having a hard time because there is 2-3 then the radical 11 Please help I know that I multiply the conjuate but from there I am stuck.  Thank you\r<BR>\n" );
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document.write( "5<BR>\n" );
document.write( "____<BR>\n" );
document.write( "2-3 radical 11 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #164436 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=164436\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I trying to rationalize the denominator but I am having a hard time because there is 2-3 then the radical 11 Please help I know that I multiply the conjuate but from there I am stuck. Thank you \r<BR>\n" );
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document.write( "5<BR>\n" );
document.write( "____<BR>\n" );
document.write( "2-3sqrt(11)\r<BR>\n" );
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document.write( "Multiply numerator and denominator by the conjugate to get:<BR>\n" );
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document.write( "[5(2-3sqrt(11)]/[(2-3sqrt(11))(2+3sqrt(11)]<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "= (10-15sqrt(11)/(4-9*11)<BR>\n" );
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document.write( "= (2 - 3sqrt(11))/(-19)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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