document.write( "Question 29734: How do I solve this problem? Could you please show all work. We are working on interpolating and I need help, thanks in advance you guys are great. I was given the following table and problem.\r
\n" ); document.write( "\n" ); document.write( "Monthly life insurance premiums per 10,000 coverage for female non smokers\r
\n" ); document.write( "\n" ); document.write( "age / monthly life insurance premium per $10,000 coverage\r
\n" ); document.write( "\n" ); document.write( "20 / $2.00
\n" ); document.write( "30 / $3.16
\n" ); document.write( "40 / $4.32
\n" ); document.write( "50 / $5.48
\n" ); document.write( "60 / $6.64
\n" ); document.write( "If the premium is $6.90 for $20,000 coverage, find the womans age
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Algebra.Com's Answer #16442 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Every 10 years the premium goes up $1.16
\n" ); document.write( "$6.90 is 26 cents higher than the premium for a women
\n" ); document.write( "who is 60 years old.
\n" ); document.write( "Set up a proportion to see
\n" ); document.write( "26/116 = x/10
\n" ); document.write( "x=260/116=2.24 years
\n" ); document.write( "The woman is 2.24 or approximately 2 years and 3 month older that 60.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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