document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=218324>Question 218324</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Select the correct answer: 1st 2nd 3rd 4th\r<BR>\n" );
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document.write( "\"The Point (-6,3) would be graphed in this quadrent.\"\r<BR>\n" );
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document.write( "Please help if you can!<BR>\n" );
document.write( "THANKS! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #164408 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=164408\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, plot the point (-6,3). \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28500%2C500%2C-10%2C10%2C-10%2C10%2C%0D%0Agraph%28500%2C500%2C-10%2C10%2C-10%2C10%2C0%29%2C%0D%0Acircle%28-6%2C3%2C0.05%29%2Ccircle%28-6%2C3%2C0.08%29%2Ccircle%28-6%2C3%2C0.10%29%2Ccircle%28-6%2C3%2C0.12%29%2Ccircle%28-6%2C3%2C0.15%29%0D%0A%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now recall that the xy plane is divided into 4 quadrants in which the first quadrant is in the upper right corner, the second is in the upper left, and it continues clockwise from here. In other words, we have\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" src=\"http://mathworld.wolfram.com/images/eps-gif/Quadrant_1000.gif\"><BR>\n" );
document.write( "Source: <a  rel=nofollow HREF=\"http://mathworld.wolfram.com/Quadrant.html\">Mathworld</a>\r<BR>\n" );
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document.write( "So comparing the two images, we see that the point (-6,3) is in the second quadrant.\r<BR>\n" );
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