document.write( "Question 29728: my daughter is working on substituion methods in her chapter system of equations and inequalities
\n" ); document.write( "trouble with this problem
\n" ); document.write( "5x-y=1
\n" ); document.write( "3x+y=1
\n" ); document.write( "any help is greatly appreciated
\n" ); document.write( "thank you \n" ); document.write( "
Algebra.Com's Answer #16439 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Solve the 1st equation for \"y\", as follows:
\n" ); document.write( "5x-y=1
\n" ); document.write( "Add \"y\" to both sides of the equation to get:
\n" ); document.write( "5x=y+1
\n" ); document.write( "Subtract \"1\" from both sides to get:
\n" ); document.write( "y=5x-1
\n" ); document.write( "Now, substitute that value of \"y\" into the 2nd equation, as follows:
\n" ); document.write( "3x+5x-1=1
\n" ); document.write( "8x=2
\n" ); document.write( "x=2/8
\n" ); document.write( "x=1/4
\n" ); document.write( "Substitute that value of \"x\" into \"y=5x-1\" as follows:
\n" ); document.write( "y=5(1/4)-1
\n" ); document.write( "y=(5/4)-(4/4)
\n" ); document.write( "y=1/4
\n" ); document.write( "So the solution for the two original equatins is
\n" ); document.write( "x=1/4, y=1/4
\n" ); document.write( "You might check that answer in the two original equations.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
\n" );