document.write( "Question 218221: part of $20000 is to be invested at 9% and the remainder is to be invested at 12%. What is the least amount of money that can be invested at 12% in order to have a yearly income of at least $2250 from the two investments? \n" ); document.write( "
Algebra.Com's Answer #164356 by stanbon(75887)\"\" \"About 
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part of $20000 is to be invested at 9% and the remainder is to be invested at 12%. What is the least amount of money that can be invested at 12% in order to have a yearly income of at least $2250 from the two investments?
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\n" ); document.write( "0.09x + 0.12(20,000-x) = 2250
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\n" ); document.write( "9x + 12*20,000 - 12x = 225000
\n" ); document.write( "-3x = 225000-240,000
\n" ); document.write( "-3x = -15000
\n" ); document.write( "x = $5000
\n" ); document.write( "20,000-x = $15,000 (amt invested at 12%)\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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