document.write( "Question 218221: part of $20000 is to be invested at 9% and the remainder is to be invested at 12%. What is the least amount of money that can be invested at 12% in order to have a yearly income of at least $2250 from the two investments? \n" ); document.write( "
Algebra.Com's Answer #164356 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! part of $20000 is to be invested at 9% and the remainder is to be invested at 12%. What is the least amount of money that can be invested at 12% in order to have a yearly income of at least $2250 from the two investments? \n" ); document.write( "------------------------------------- \n" ); document.write( "0.09x + 0.12(20,000-x) = 2250 \n" ); document.write( "--- \n" ); document.write( "9x + 12*20,000 - 12x = 225000 \n" ); document.write( "-3x = 225000-240,000 \n" ); document.write( "-3x = -15000 \n" ); document.write( "x = $5000 \n" ); document.write( "20,000-x = $15,000 (amt invested at 12%)\r \n" ); document.write( "\n" ); document.write( "===================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |