document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=218207>Question 218207</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone help me with this please. IF f(x)=3x+1, and g(x)=(x^*2+5x)^*-1/2, find g(f(x)). Any explanation on how to do it would be appreciated.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #164346 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=164346\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Can someone help me with this please. IF f(x)=3x+1, and g(x)=(x^*2+5x)^*-1/2, find g(f(x)).<BR>\n" );
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document.write( "g[f(x)] = g[3x+1]<BR>\n" );
document.write( "= [(3x+1)^2+5x)^(-1/2)]<BR>\n" );
document.write( "= [(3x^2+6x+1+5x)^(-1/2)]<BR>\n" );
document.write( "---<BR>\n" );
document.write( "= 1/sqrt(3x^2+11x+1)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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