document.write( "Question 218172: I need help finding the equation of the upper half of the circle and the domain.
\n" ); document.write( "\"+x%5E2%2By%5E2=10+\"\r
\n" ); document.write( "\n" ); document.write( "I am particularly having trouble finding the domain.\r
\n" ); document.write( "\n" ); document.write( "Thank you in advance.
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Algebra.Com's Answer #164335 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
equation of the circle is x^2 + y^2 = 10
\n" ); document.write( "solve for y:
\n" ); document.write( "y^2 = 10-x^2
\n" ); document.write( "y = +/- sqrt(10-x^2))
\n" ); document.write( "You want the upper half of the circle only, so you want:
\n" ); document.write( "y = sqrt(10-x^2))
\n" ); document.write( "You will reject y = -sqrt(10-x^2) because that would give you the bottom half of the circle which you don't want.
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\n" ); document.write( "Your domain is determined by sqrt(10-x^2))
\n" ); document.write( "Your domain has to result in real values of y in your range.
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\n" ); document.write( "If sqrt(10-x^2) is positive or 0, then your equation is valid because that would result in real values of y in your range.
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\n" ); document.write( "If sqrt(10-x^2) is negative, then your equation is invalid because you would have the square root of a negative number which would not result in real values of y in your range.
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\n" ); document.write( "You need to find out when 10-x^2 is >= 0
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\n" ); document.write( "add x^2 to both sides of this equation to get:
\n" ); document.write( "10 >= x^2
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\n" ); document.write( "multiply both sides of this equation by -1 to get:
\n" ); document.write( "-10 <= -x^2
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\n" ); document.write( "add x^2 to both sides of this equation and add 10 to both sides of this equation to get:
\n" ); document.write( "x^2 <= 10
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\n" ); document.write( "Your domain will result in real values of y in your range when x^2 <= 10.
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\n" ); document.write( "x^2 is <= 10 when x < sqrt(10) and when -x > - sqrt(10)
\n" ); document.write( "Let x = sqrt(10), then x^2 = 10
\n" ); document.write( "Let x = -sqrt(10), then x^2 = 10
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\n" ); document.write( "Your domain is when -sqrt(10) <= x <= sqrt(10)
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\n" ); document.write( "A graph of your equation is shown below:
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\n" ); document.write( "\"graph%28300%2C300%2C-5%2C5%2C-5%2C5%2Csqrt%2810-x%5E2%29%29\"
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\n" ); document.write( "since sqrt(10) = +/- 3.16227766, the graph looks accurate as far as the naked eye can see.
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