document.write( "Question 218140: A student needs to put a 60% antifreeze solution in his car. If his car holds 10 quarts of antifreeze and he only has jugs of a 30% and 80% solution, how much of each solution should be used to fill his car? \n" ); document.write( "
Algebra.Com's Answer #164305 by RAY100(1637)\"\" \"About 
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Let x = amt of 30%
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\n" ); document.write( "Let y = amt of 80%
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\n" ); document.write( "x+y = 10,,,,,,,x=10-y
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\n" ); document.write( "30% *x + 80% *y = 60% *10
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\n" ); document.write( ".3x +.8y = 6,,,,,,,,,subst
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\n" ); document.write( ".3(10-y) +.8y =6
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\n" ); document.write( "3 -.3y +.8y =6
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\n" ); document.write( ".5y = 3
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\n" ); document.write( "y= 6 quarts,,,,,,,,x= 4 quarts
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\n" ); document.write( ".3(4) +.8(6) = .6(10)
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\n" ); document.write( "1.2 +4.8 = 6,,,,,,ok
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