document.write( "Question 218140: A student needs to put a 60% antifreeze solution in his car. If his car holds 10 quarts of antifreeze and he only has jugs of a 30% and 80% solution, how much of each solution should be used to fill his car? \n" ); document.write( "
Algebra.Com's Answer #164305 by RAY100(1637) ![]() You can put this solution on YOUR website! Let x = amt of 30% \n" ); document.write( ". \n" ); document.write( "Let y = amt of 80% \n" ); document.write( ". \n" ); document.write( "x+y = 10,,,,,,,x=10-y \n" ); document.write( ". \n" ); document.write( "30% *x + 80% *y = 60% *10 \n" ); document.write( ". \n" ); document.write( ".3x +.8y = 6,,,,,,,,,subst \n" ); document.write( ". \n" ); document.write( ".3(10-y) +.8y =6 \n" ); document.write( ". \n" ); document.write( "3 -.3y +.8y =6 \n" ); document.write( ". \n" ); document.write( ".5y = 3 \n" ); document.write( ", \n" ); document.write( "y= 6 quarts,,,,,,,,x= 4 quarts \n" ); document.write( ". \n" ); document.write( ".check \n" ); document.write( ". \n" ); document.write( ".3(4) +.8(6) = .6(10) \n" ); document.write( ". \n" ); document.write( "1.2 +4.8 = 6,,,,,,ok \n" ); document.write( ". \n" ); document.write( " |