document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29698>Question 29698</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i solve (2x)with an exponent of -3 outside parenthesis and all of this is over 3x with an exponent of -2..please help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16430 by </B><A HREF=/tutors/aboutme.mpl?userid=Cintchr><B>Cintchr(481)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cintchr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16430\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assuming that I am reading that in the denominator, the -2 is associated with ONLY the x, then the solution is as follows:\r<BR>\n" );
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document.write( "(2x)^-3 / 3x^-2<BR>\n" );
document.write( "Distribute the -3 to both parts of the numerator.<BR>\n" );
document.write( "(2^-3)(x^-3) / (3)(x^-2)<BR>\n" );
document.write( "If a number or variable was a negative exponent, move it to the other side of the fraction bar and make the exponent possitive.<BR>\n" );
document.write( "(x^2) / (3)(2^3)(x^3)<BR>\n" );
document.write( "Work the powers on the numbers first.<BR>\n" );
document.write( "(x^2) / (3)(8)(x^3)<BR>\n" );
document.write( "(x^2) / (24)(x^3)<BR>\n" );
document.write( "Work the division of the exponents (subtract the exponents putting the remainder in the denominator since 3 > 2)<BR>\n" );
document.write( "1 / 24x<BR>\n" );
document.write( "Done<BR>\n" );
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