document.write( "Question 218132: Find two positive numbers so that twice the sum equals their product and one number is 6 times the other number \n" ); document.write( "

Algebra.Com's Answer #164298 by RAY100(1637) $\"\"$ $\"About$

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Let x &y = numbers
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\n" ); document.write( "x=6y
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\n" ); document.write( "2(x+y) = xy,,,,,,,,substitute
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\n" ); document.write( "2{6y+y} ={6y}y
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\n" ); document.write( "14y =6y^2
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\n" ); document.write( "0=6y^2 -14y
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\n" ); document.write( "0 = y(6y-14) =0
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\n" ); document.write( "y=0,,,,,,,,,y=14/6 = 7/3
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\n" ); document.write( "x=0,,,,,,,,,x= 14
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\n" ); document.write( "check,,,,(0,0),,,,0=0,,,,,ok,,,but not positive number
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\n" ); document.write( "(14,7/3),,,,,2(14+7/3) = (14)(7/3) = 32.67,,,,,ok
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