document.write( "Question 217822: On the first part of a 317-mile trip, a salesperson average 58 miles per hour. The salesperson averaged only 52 miles per hour on the last part of the trip because of an increased volume of traffic. The total time of the trip was 5 hours and 45 minutes. Find the amount of time at each of the two speeds.
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Algebra.Com's Answer #164261 by ankor@dixie-net.com(22740)\"\" \"About 
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On the first part of a 317-mile trip, a salesperson average 58 miles per hour.
\n" ); document.write( " The salesperson averaged only 52 miles per hour on the last part of the trip
\n" ); document.write( " because of an increased volume of traffic.
\n" ); document.write( " The total time of the trip was 5 hours and 45 minutes. Find the amount of time at each of the two speeds.
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\n" ); document.write( "Convert 5 hr 45 min to 5.75 hr
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\n" ); document.write( "Let t = travel time at 58 mph
\n" ); document.write( "then
\n" ); document.write( "(5.75-t) = travel time at 52 mph
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\n" ); document.write( "Write a distance equation: Dist = speed * time
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\n" ); document.write( "Dist at 58mph + dist at 52mph = 317 mi
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\n" ); document.write( "58t + 52(5.75-t) = 317
\n" ); document.write( "58t + 299 - 52t = 317
\n" ); document.write( "58t - 52t = 317 - 299
\n" ); document.write( "6t = 18
\n" ); document.write( "t = 3 hrs at 58 mph
\n" ); document.write( "then
\n" ); document.write( "5.75 - 3 = 2.75 hrs at 52 mph
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\n" ); document.write( "Check solution by finding the total dist
\n" ); document.write( "58(3) + 52(2.75) =
\n" ); document.write( "174 + 143 = 317 mi; confirms our solutions \n" ); document.write( "
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