document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=217891>Question 217891</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The problem is:<BR>\n" );
document.write( "3x+2y=4<BR>\n" );
document.write( "2x-3y=6\r<BR>\n" );
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document.write( "I can only get so far in this problem and then I'm stuck. Here's how far I can get:\r<BR>\n" );
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document.write( "3x=-2y+4            \r<BR>\n" );
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document.write( "3x/3=-2/3y+4/3\r<BR>\n" );
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document.write( "x=-2/3y+4/3<BR>\n" );
document.write( "Now if I substitute this into the 2nd equation, I have:<BR>\n" );
document.write( "2(-2/3y+4/3)-3y=6\r<BR>\n" );
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document.write( "This is where I get stuck, it doesn't make any sense. I have looked in the back of the student manual that works with my textbook ( Miller//O'Neil//Hyde: Beginning & Intermediate Algebra, 2nd edition) and it just doesn't click. Any help would be greatly appreciated!\r<BR>\n" );
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document.write( "Lisa\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #164232 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=164232\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x=-2y+4         <BR>\n" );
document.write( "3x/3=-2y/3+4/3<BR>\n" );
document.write( "x=-2y/3+4/3<BR>\n" );
document.write( "Now if I substitute this into the 2nd equation 2x-3y=6, I have:<BR>\n" );
document.write( "2(-2y/3+4/3)-3y=6<BR>\n" );
document.write( "-4y/3+8/3-3Y=6<BR>\n" );
document.write( "-4Y/3-3Y=6-8/3 combine the y terms by finding a common denominator (3).<BR>\n" );
document.write( "(-4Y-3Y*3)/3=(6*3-8)/3<BR>\n" );
document.write( "(-4Y-9Y)/3=(18-8)/3 cancel out the 3 in the denominators.<BR>\n" );
document.write( "-13y=10<BR>\n" );
document.write( "y=-10/13 ans.<BR>\n" );
document.write( "Replace y by (-10/13) in the first equation. <BR>\n" );
document.write( "3x=-2(-10/13)+4<BR>\n" );
document.write( "3x=20/13+4 divide both sides by 3.<BR>\n" );
document.write( "x=20/13*1/3+4/3<BR>\n" );
document.write( "x=20/39+4/3 find the common denominator (39).<BR>\n" );
document.write( "x=(20+4*13)/39<BR>\n" );
document.write( "x=(20+52)/39<BR>\n" );
document.write( "x=72/39 reduce the fraction.<BR>\n" );
document.write( "x=24/13 ans.<BR>\n" );
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