document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=217905>Question 217905</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The lengths of the sides of a triangle are all whole numbers.  The triangle has a perimeter (distance around the shape) of M units.  If someone gives you a value for M, determine the shortest possible length of a side.\r<BR>\n" );
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document.write( "this is a problem my teacher asigned us for the wekkend i have worked on it for two hourrs but nothing is making sense. im not sure what to do at all. PLEASE HELP ME </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #164220 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=164220\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> YOU DIDN'T STATE THAT THIS TRIANGLE IS A RIGHT TRIANGLE OR NOT. <BR>\n" );
document.write( "IT DOES MAKE A DIFFERENCE.<BR>\n" );
document.write( "PERIMETER (M)=A+B+C FOR ALL TRIANGLES.<BR>\n" );
document.write( "LET M=12<BR>\n" );
document.write( "A RIGHT TRIANGLE COULD BE:<BR>\n" );
document.write( "3+4+5=12<BR>\n" );
document.write( "BECAUSE 3^3+4^2=5^2<BR>\n" );
document.write( "9+16=25 <BR>\n" );
document.write( "25=25 THUS THE SMALLER SIDE WOULD BE 3.<BR>\n" );
document.write( "HOWEVER A NON-RIGHT TRIANGLE WOULD HAVE A DIFFERENT SOLUTION GIVEN AN (M) VALUE.<BR>\n" );
document.write( "TRY (M)=47<BR>\n" );
document.write( "THE SHORTEST SIDE COULD BE 1.<BR>\n" );
document.write( "A+B+C=47<BR>\n" );
document.write( "1+B+C=47<BR>\n" );
document.write( "1+23+23=47 (THIS TECHNIQUE WORKS AS LONG AS THE DIFFERENCE BETWEEN THE B & C SIDES IS < THE A SIDE.)<BR>\n" );
document.write( "47=47<BR>\n" );
document.write( "THIS WORKS FOR ANY PERIMETER = AN ODD NUMBER.<BR>\n" );
document.write( "LETS TRY AN EVEN NUMBER:<BR>\n" );
document.write( "(M)=74<BR>\n" );
document.write( "A+B+C=74<BR>\n" );
document.write( "2+B+C=74<BR>\n" );
document.write( "2+36+34=74 (AGAIN THE DIFFERENCE BETWEEN B & C IS < A SIDE.)<BR>\n" );
document.write( "74=74\r<BR>\n" );
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