document.write( "Question 217921: simplify i^29 \n" ); document.write( "
Algebra.Com's Answer #164200 by RAY100(1637)\"\" \"About 
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i = sqrt (-1) =i
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\n" ); document.write( "i^2 = (-1)
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\n" ); document.write( "i^3 = -i
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\n" ); document.write( "i^4 = +1
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\n" ); document.write( "and then they repeat,,,every 4
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\n" ); document.write( "i^5 = sqrt(-1)
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\n" ); document.write( "etc
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\n" ); document.write( "Since it the pattern does repeat for every 4th power,,
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\n" ); document.write( "to find any power,,,divide by 4,,,and the REMAINDER is the power of concern,
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\n" ); document.write( "for example,,i^5 =(5/4 = 1 R1)= i^1 =i= sqrt(-1)
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\n" ); document.write( " for this problem,,,i^29 = (29/4 =7R1)=i^1 =i =sqrt(-1)
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